Digit cancelling fractions
Problem 33
The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplify it may incorrectly believe that 49/98 = 4/8, which is correct, is obtained by cancelling the 9s.
We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
There are exactly four non-trivial examples of this type of fraction, less than one in value, and containing two digits in the numerator and denominator.
If the product of these four fractions is given in its lowest common terms, find the value of the denominator.
from tools import gcd
def run():
n_total, d_total = 1, 1
for d in range(10, 100):
d2 = d % 10
if d2 == 0:
continue
d1 = d // 10
for n in range(10, d):
n2 = n % 10
if n2 == 0:
continue
n1 = n // 10
ok = False
if n1 == d1 and n * d2 == d * n2:
ok = True
elif n1 == d2 and n * d1 == d * n2:
ok = True
elif n2 == d2 and n * d1 == d * n1:
ok = True
elif n2 == d1 and n * d2 == d * n1:
ok = True
if ok:
n_total *= n
d_total *= d
g = gcd(n_total, d_total)
return d_total // g