Self powers

Problem 48

The series, 11 + 22 + 33 + ... + 1010 = 10405071317.
Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.
def run():
    # str(sum([i**i for i in range(1,1001)]))[-10:]
    total = 0
    x = 1
    while x < 1001:
        total += x**x
        x += 1
    return str(total)[-10:]