GCD of Divisors

Problem 530

Every divisor d of a number n has a complementary divisor n/d.
Let f(n) be the sum of the greatest common divisor of d and n/d over all positive divisors d of n, that is.
Let F be the summatory function of f, that is.
You are given that F(10)=32 and F(1000)=12776.
Find F(1015).