{"app":{"locale":"en-GB"},"problem":{"content":"

Let $\\sigma(n)$ be the sum of the divisors of $n$.
E.g. the divisors of 4 are 1, 2 and 4, so $\\sigma(4)=7$.

The numbers $n$ not exceeding 20 such that 7 divides $\\sigma(n)$ are: 4,12,13 and 20, the sum of these numbers being 49.

Let $S(n , d)$ be the sum of the numbers $i$ not exceeding $n$ such that $d$ divides $\\sigma(i)$.
So $S(20 , 7)=49$.

You are given: $S(10^6,2017)=150850429$ and $S(10^9 , 2017)=249652238344557$.

Find $S(10^{11} , 2017)$

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